The mean of 50 observations was 36
SpletFind the probability that the mean of a sample of size 36 will be within 10 units of the population mean, that is, between 118 and 138. ... Find the probability that in a sample of 50 returns requesting a refund, the mean such time will be more than 50 days. Scores on a common final exam in a large enrollment, multiple-section freshman course ... Splet09. jun. 2024 · The mean and standard deviation of 50 observations are 15 and 2 respectively. It was found that one incorrect observation was taken such that the sum of correct and incorrect observations is 70. If the correct mean is 16, then the correct variance is equal to : A 10 B 36 C 43 D 60 Check Answer 2 JEE Main 2024 (Online) 26th June …
The mean of 50 observations was 36
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SpletA sample of 36 observations is selected from a normal population. The sample mean is 21, and the population standard deviation is 5. Conduct the following test of hypothesis using the .05 significance level. ... The sample mean is 102. A sample of 50 observations is selected from a second population with a population standard deviation of 6 ... SpletOn April 14, 2024 at 10:45:36 ET an unusually large $274.98K block of Put contracts in CarMax (KMX) was bought, with a strike price of $67.50 / share, expiring in 98 day(s) (on July 21, 2024).
SpletThen Y ~ N(172.36, 6.34). The mean height of 15 to 18-year-old males from Chile from 2009 to 2010 was 170 cm with a standard deviation of 6.28 cm. Male heights are known to follow a normal distribution. ... 6 = 44 and 50 + 6 = 56 are within one standard deviation of the mean 50. The z-scores are –1 and +1 for 44 and 56, respectively. SpletCoastal water regions represent some of the most fragile ecosystems, exposed to both climate change and human activities. While remote sensing provides unprecedented amounts of data for water quality monitoring on regional to global scales, the performance of satellite observations is frequently impeded by revisiting intervals and unfavorable …
SpletThe arithmetic mean of a group of 100 observations was calculated as 63. It was later found that one observation was wrongly taken as 75 instead of 65. The correct mean is (A) 63.1 (B) 63 (C) 62.9 (D) 73 Answer: (C) 62.9 15. Mean of 100 items and their standard deviation is 20. Then the sum of squares of all the items is Splet= 400 - 15 + 45 = 400 + 30 = 430 Correct mean = correct sum / number of observation = 430/10 = 43 Therefore, the correct mean is 43. Try This: The mean of 12 observations was calculated as 50. It was detected on rechecking that the value of 35 was wrongly copied as 65. Find the correct mean.
Splet13. jul. 2024 · The mean and standard deviation of 50 observations are 15 and 2 respectively. It was found that one incorrect observation was taken such that the sum of …
SpletSolutions for The mean of 50 observations was 36. It was found later that an observation 48 was wringly taken as 23. The corrected new mean is:a)35.2b)36.1c)36.5d)39.1Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Banking Exams. dalmolin motoresSpletThe mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is? - Quora Answer (1 of 3): 50 observations sum/50=36 50 observation sum=50*36=1800 Then 48 taken wrongly as 23 48–23=25 Then real sum of 50 observation=1800+25=1825 Then 1825/50=36.5 dal molin itSplet11. jul. 2024 · The mean and standard deviation of 50 observations are 15 and 2 respectively. If it was found that one incorrect observation was taken such that the sum of correct and incorrect observations is 70 . If the correct mean is 16 , then the correct variance is equal to ? class-12 Please log in or register to answer this question. 1 Answer … marine corps travel orderSpletThe mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is___________? A. 35.2 B. 36.1 C. 36.5 D. 39.1 … marine corps triviaSpletThe mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The correct (new) mean is : A) 35.2 B) 36.1 C) 36.5 D) 39.1 Correct Answer: C) 36.5 Description for Correct answer: According to the question, Correct observation = 50 × 36 + 48 − 23 50 = 1800 + 25 50 = 1825 50 = 36.5 dalmolin motorsSpletThe mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is : Answer: B) 36.5 Explanation: Correct Sum = (36 … dal molin luca geologoSplet26. mar. 2024 · Equation 6.1.2 says that averages computed from samples vary less than individual measurements on the population do, and quantifies the relationship. Example 6.1. 2. The mean and standard deviation of the tax value of all vehicles registered in a certain state are μ = $ 13, 525 and σ = $ 4, 180. marine corps trial counsel assistance program